SOLUTION: i have two rectangles that have the same area. one's width is x and its length is 2x+2 and the other's width is x+3 and its length is x+1. i need to find x
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-> SOLUTION: i have two rectangles that have the same area. one's width is x and its length is 2x+2 and the other's width is x+3 and its length is x+1. i need to find x
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Question 825799: i have two rectangles that have the same area. one's width is x and its length is 2x+2 and the other's width is x+3 and its length is x+1. i need to find x Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! x*(2x+2)=(x+3)*(x+1)
2x^2+2x = x^2+4x+3
x^2-2x-3 = 0
x=-1 disregard
which leaves
x=3
(3,8) and (6,4)
