SOLUTION: Julia's soybean field is 3m longer than it is wide. To increase production, she plans to increase both the length and width by 2m. If the new field is 46m^2 larger than the old f
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-> SOLUTION: Julia's soybean field is 3m longer than it is wide. To increase production, she plans to increase both the length and width by 2m. If the new field is 46m^2 larger than the old f
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Question 824556: Julia's soybean field is 3m longer than it is wide. To increase production, she plans to increase both the length and width by 2m. If the new field is 46m^2 larger than the old field, then what are the dimension of the old field?
You can put this solution on YOUR website! ---
x = length
y = width
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x = y + 3
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area of old field:
a = xy
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area of new field:
A = (x + 2)(y + 2)
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A = a + 46
(x + 2)(y + 2) = xy + 46
xy + 2x + 2y + 4 = xy + 46
2x + 2y = 42
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system of linear equations:
x = y + 3
2x + 2y = 42
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put the system of linear equations into standard form
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x - y = 3
2x + 2y = 42
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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answer:
x = length = 12 m
y = width = 9 m
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