SOLUTION: The length of a rectangle is 3in more than twice its width. If the perimeter of the rectangle is 36in, find the width of the rectangle.
(a)7in
(b)6in
(c)4in
(d)5in
Algebra ->
Rectangles
-> SOLUTION: The length of a rectangle is 3in more than twice its width. If the perimeter of the rectangle is 36in, find the width of the rectangle.
(a)7in
(b)6in
(c)4in
(d)5in
Log On
Question 82261: The length of a rectangle is 3in more than twice its width. If the perimeter of the rectangle is 36in, find the width of the rectangle.
(a)7in
(b)6in
(c)4in
(d)5in Answer by tutorcecilia(2152) (Show Source):
You can put this solution on YOUR website! Use the formula for the perimeter of a rectangle:
P=2(length+width)
P=36
Length = 3in more than twice its width = 2 x Width +3 = 2w+3
Width=w
.
P=2(l+w) [plug-in the values and solve for the width(w)]
36=2[(2w+3)+w]
36/2=2/2(2x+3+w)
18=2w+3+w
18=3w+3
18-3=3w
15=3w
15/3=3w/3
5=w
.
checking:
Length = 2w+3=2(5)+3=13
Width=5
.
36=2(13+5)
36=2(18)
36=36 [checks out]
