SOLUTION: The length of a rectangle is 3 more than 5 times its width with a perimeter of 66 inches what are the dimensions?

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Question 811401: The length of a rectangle is 3 more than 5 times its width with a perimeter of 66 inches what are the dimensions?
Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
The equation for the perimeter of a rectangle is P = 2L + 2W.
Equation 1: 66+=+2L+%2B+2W
Equation 2: L+=+3+%2B+5W
Plug (3 + 5W) into equation 1 for L.
66+=+2%2A%283+%2B+5W%29+%2B+2W
Multiply the 2 through.
66+=+6+%2B+10W+%2B+2W
Combine like terms.
66+=+6+%2B+12W
Subtract 6 from both sides.
60+=+12W
Divide both sides by 12.
highlight%285+=+W%29
Now plug 5 into equation 2 for W and solve for L.
Equation 2: L+=+3+%2B+5W
L+=+3+%2B+5%2A%285%29
highlight_green%28L+=+28%29