SOLUTION: square folded in half results in rectangle with perimeter of 39..the original area of the square is... i calculate it to be 13 x 13..which is 169..am i correct?

Algebra ->  Rectangles -> SOLUTION: square folded in half results in rectangle with perimeter of 39..the original area of the square is... i calculate it to be 13 x 13..which is 169..am i correct?      Log On


   

Question 796110: square folded in half results in rectangle with perimeter of 39..the original area of the square is...
i calculate it to be 13 x 13..which is 169..am i correct?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Yes.
x= length of the side of the square.
Folding the square in half, you get a rectangle with length x and width x%2F2
Its perimeter would be
2%2Ax%2B2%2A%28x%2F2%29=39
2x%2Bx=39
3x=39
x=39%2F3
x=13
The area of a square with side length 13 is
13%2A13=13%5E2=169