SOLUTION: A rectangle has a perimeter of 56 feet. If the length is 2feet less than twice the width what is the demensions
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Question 783362: A rectangle has a perimeter of 56 feet. If the length is 2feet less than twice the width what is the demensions Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Width = x
Length = 2x - 2
Perimeter = 2*length + 2*width
56 = 2*x + 2*(2x - 2)
56 = 2x + 4x - 4
6x = 56 + 4
6x = 60
x = 10ft
Width = 10ft
Length = 18ft
Hope this helps.
:-)
