SOLUTION: Find the maximum area of a rectangle whose perimeter is 18 inches.

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Question 774482: Find the maximum area of a rectangle whose perimeter is 18 inches.
Answer by reviewermath(1029) About Me  (Show Source):
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Q:
Find the maximum area of a rectangle whose perimeter is 18 inches.
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A:
Let x be the length and y be the width of a rectangle.
Perimeter, P = 2x + 2y = 18
So x + y = 9 or y = 9 - x
Area, A = xy = x(9 - x)
A = 9x+-+x%5E2
A is a quadratic function.
A has a maximum value because the coefficient of x%5E2 is negative.
To get the maximum value, we compute the vertex (h,k) where h = -b%2F2a and k = %284ac+-+b%5E2%29%2F%284a%29.
In 9x+-+x%5E2, a = -1, b = 9, and c = 0.
So h = -b%2F2a = -9%2F%282%28-1%29%29 = 9%2F2 is the length.
and k = %284%28-1%29%280%29+-+%289%29%5E2%29%2F%284%28-1%29%29 = 81%2F4 is the area.
Therefore the maximum area of a rectangle is highlight%2881%2F4%29 square inches.