SOLUTION: Stan wants to make a rectangular garden. He has 34 ft. of fencing to put around the perimeter. If the length is to be 5ft. more than the width, find the dimensions of the planned g

Algebra ->  Rectangles -> SOLUTION: Stan wants to make a rectangular garden. He has 34 ft. of fencing to put around the perimeter. If the length is to be 5ft. more than the width, find the dimensions of the planned g      Log On


   

Question 769504: Stan wants to make a rectangular garden. He has 34 ft. of fencing to put around the perimeter. If the length is to be 5ft. more than the width, find the dimensions of the planned garden.
Found 2 solutions by John10, 55305:
Answer by John10(297) About Me  (Show Source):
You can put this solution on YOUR website!
Stan wants to make a rectangular garden. He has 34 ft. of fencing to put around the perimeter. If the length is to be 5ft. more than the width, find the dimensions of the planned garden.
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We will set up two linear equations to solve this problem:
Let L be the length and W is the width
The first equation is about the perimeter:
Perimeter = 2L + 2W = 34 or L + W = 17
The second equation is the length is 5 ft more than the width
L = 5 + W
So we have the system of 2 equations:
L + W = 17
L = W + 5
You can use the substitution method to solve for L and W
Hope it helps you
John10 (john100185@yahoo.com)

Answer by 55305(86) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose we assume the width to be x. The length is then x%2B5.
The perimeter of a rectangle is 2(l+w), where l is the length and w is the width.
In this problem, the perimeter is 34, which means that 2%28x%2Bx%2B5%29=34. Dividing both sides by 2 and simplifying, we get 2x+5=17. Subtracting 5 from both sides, we then find that 2x=12 and x=6.
The width is 6 and the length is 11.