SOLUTION: the length of a rectangle is 3 yd less than twice its width, and the area of the rectangle is 27^2. find the dimensions
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Question 764026: the length of a rectangle is 3 yd less than twice its width, and the area of the rectangle is 27^2. find the dimensions Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Width = x
Length = 2x - 3
x(2x - 3) = 27
2x^2 - 3x - 27 = 0
(2x - 9)(x + 3) = 0
2x - 9 = 0
2x = 9
x = 4.5 yds
x + 3 = x = -3(no answer)
Width = 4.5 yards
Length = 6 yards (2(4.5) - 3)
Hope this helps.
:-)
