SOLUTION: Anyone willing o help me? I don't get this at all I can give you the question and some additional info but after hat I am so lost! Thanks for your time!
You think it would b
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-> SOLUTION: Anyone willing o help me? I don't get this at all I can give you the question and some additional info but after hat I am so lost! Thanks for your time!
You think it would b
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Question 743452: Anyone willing o help me? I don't get this at all I can give you the question and some additional info but after hat I am so lost! Thanks for your time!
You think it would be a great idea to market 22 gallon aquarium that is perfect cube. estimate the dimensions and then check your guess to see how close you can get . What operation do you need to know to get an exact answer?
Common aquarium holds 10 gallons. I know volume of a right rectangular tank is found by multiplying the length of the tank times the width times the height, or V=lwh. I know 231 cubic inches are equal to 1 gallon. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! You think it would be a great idea to market 22 gallon aquarium that is perfect cube. estimate the dimensions and then check your guess to see how close you can get . What operation do you need to know to get an exact answer?
Common aquarium holds 10 gallons. I know volume of a right rectangular tank is found by multiplying the length of the tank times the width times the height, or V=lwh. I know 231 cubic inches are equal to 1 gallon.
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Total volume = 22*231 = 5082 cu in
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Since the aquarium is a cube all the dimensions are the same.
Each side is cbrt(5082) = 17.19 inches
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Cheers,
Stan H.
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