SOLUTION: Find the dimentions of a rectangle whose lenth is one foot longer than twice its width and whose perameter is 20 feet.
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Question 705761: Find the dimentions of a rectangle whose lenth is one foot longer than twice its width and whose perameter is 20 feet. Answer by Stitch(470) (Show Source):
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Equation 1:
Equation 2: (The perimeter of a rectangle
P = 20
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Since equation 1 is already solved for L, plug (2W + 1) into equation 2 for L
Equation 2:
Multiply the 2 through
Combine like terms
Subtract 2 from both sides
Divide both sides by 6
Now plug 3 into equation 1 for W
Equation 1:
(