SOLUTION: The length of a rectangle is a = 3 cm less than twice the width. Express as an integer the maximum width of the rectangle when the perimeter is less than 69 cm. All I have so fa

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is a = 3 cm less than twice the width. Express as an integer the maximum width of the rectangle when the perimeter is less than 69 cm. All I have so fa      Log On


   



Question 703819: The length of a rectangle is a = 3 cm less than twice the width. Express as an integer the maximum width of the rectangle when the perimeter is less than 69 cm.
All I have so far is 2W-a
I really just need to figure out how to set up the problem. The answer would be great as well so I can check my answer after working it out. Thank you so much for the assistance.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
This is not really a maximization problem, but you know you want less than 69 cm. perimeter.

Description gave:
w = width
a = 2w-3

Perimeter, p=2a+2w,
p=2(2w-3)+2w
p=6w-6

The perimeter condition,
6w-6<69
6w<69+6
6w<75
w<12.5