SOLUTION: The perimeter of a rectangle is 328 ft. It's length is three times its width. What's the length of the rectangle?

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is 328 ft. It's length is three times its width. What's the length of the rectangle?       Log On


   



Question 691097: The perimeter of a rectangle is 328 ft. It's length is three times its width. What's the length of the rectangle?

Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
Set-Up
--------------
L = length
W = width
Equation 1: 328+=+2L+%2B+2W
Equation 2: L+=+3W
Solution:
--------------
Plug 3W into equation 1 for L
Equation 1: 328+=+2L+%2B+2W
328+=+2%283W%29+%2B+2W Simplify
328+=+6W+%2B+2W Combine like terms
328+=+8W Divide both sides by 6
highlight%2841+=+W%29
Now plug 41 into equation 2 for W
Equation 2: L+=+3W
L+=+3%2A%2841%29
highlight_green%28L+=+123%29