SOLUTION: The width of a rectangle is 53 yd. Find all possible lengths such that the perimeter of the rectangle will be atleast 486yd.
Algebra ->
Rectangles
-> SOLUTION: The width of a rectangle is 53 yd. Find all possible lengths such that the perimeter of the rectangle will be atleast 486yd.
Log On
Question 679931: The width of a rectangle is 53 yd. Find all possible lengths such that the perimeter of the rectangle will be atleast 486yd. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The width of a rectangle is 53 yd. Find all possible lengths such that the perimeter of the rectangle will be atleast 486yd.
---------
Perimeter = 2(length + width)
486 <= 2(x + 53)
x+53 >= 243
----
length >= 190
---------
Cheers,
Stan H.
=========
(