SOLUTION: The width of a rectangle is x inches long. The length of that rectangle is 6 inches less than twice the width. If the perimeter measures 48 inches, what is the measure of the le

Algebra ->  Rectangles -> SOLUTION: The width of a rectangle is x inches long. The length of that rectangle is 6 inches less than twice the width. If the perimeter measures 48 inches, what is the measure of the le      Log On


   

Question 676695: The width of a rectangle is x inches long. The length of that rectangle is 6 inches less than
twice the width. If the perimeter measures 48 inches, what is the measure of the length
and width of the rectangle.
Answer by rm29924(97) About Me  (Show Source):
You can put this solution on YOUR website!
the formula for the perimeter of a rectangle is perimeter=2(length)+2(width)
the width=x
the length is 6 inches less than twice the width
twice the width is 2x and six inches less means subtract 6
the length=2x-6
the perimeter = 48 inches
48=2(2x-6)+2x
48=4x-12+2x
combine like terms
48=6x-12
add 12 to both sides
60=6x
divide both sides by 6 to get x by itself
10=x
we know the length is 2x-6
2(10)-6
20-6
14
answer: the length is 14 inches
you can plug the answers into the equation to check it