SOLUTION: The area is 4700 square feet. The length is twice the width minus six feet. I need help setting up the problem and solving it.

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Question 672940: The area is 4700 square feet. The length is twice the width minus six feet. I need help setting up the problem and solving it.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let The width = +w+ ft
You are given that the length = +2w+-+6+ ft
Let area = +A+
+A+ = length x width
+A+=+w%2A%28+2w+-+6+%29+ ft2
You are given that +A+=+4700+ ft2
+4700+=+w%2A%28+2w+-+6+%29+
+4700+=+2w%5E2+-+6w+
+2w%5E2+-+6w+-+4700+=+0+
Divide both sides by +2+

+a+=+1+
+b+=+-3+
+c+=+-2350+
+w+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2+-+4%2A1%2A%28-2350%29+%29%29+%2F+%282%2A1%29+
+w+=+%28+3+%2B-+sqrt%28+9+%2B+9400+%29%29+%2F+2+
+w+=+%28+3+%2B-+sqrt%28+9409+%29%29+%2F+2+
+w+=+%28+3+%2B+97+%29+%2F+2+ ( ignore the negative square root of 9409 )
+w+=+100%2F2+
+w+=+50+
+2w+-+6+=+2%2A50+-+6+
+2w+-+6+=+94+
The width is 50 ft and
the length is 94 ft
-------------------
check:
+A+=+50%2A94+
+A+=+4700+
OK