SOLUTION: The perimeter of a rectangular piece of poster board is 96in. The length is 8in. greater than the width. Find the width and the length.

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangular piece of poster board is 96in. The length is 8in. greater than the width. Find the width and the length.      Log On


   

Question 665662: The perimeter of a rectangular piece of poster board is 96in. The length is 8in. greater than the width. Find the width and the length.
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
p = 2(l) + 2(w) = 96
l = w +8
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Substitute l into the perimeter equation
2(w+8) + 2w = 96
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Distribute the 2
2w + 16 + 2w = 96
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Combine like terms
4w = 96 - 16
4w = 80
Divide both sides by 4
highlight%28w+=+20%29in
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Plug in width into the equation
2l + 2(20) = 96
2l + 40 = 96
2l = 96 - 40
2l = 56
Divide both sides by 2
highlight%28l+=+28%29in
...
Check cartoon%28%0D%0A20+%2B+8%2C+%0D%0A28%29
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