SOLUTION: I have the answer I just need to make sure it is correct. Please confirm. The length of a rectangle is 2 inches more than the width. If the length and width are each increased by

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Question 664410: I have the answer I just need to make sure it is correct. Please confirm.
The length of a rectangle is 2 inches more than the width. If the length and width are each increased by 3 inches, the perimeter of the new rectangle will be 4 inches less than 8 times the width of the original rectangle. Find the demensions.
I have for the original rectangle: Width= 5in, lenght=7in
The new rectangle I have width=8in, lenght=10in, but I had originally had 12inches for the lenght of the new rectangle, but when i checked it with the primeter, it did not work out.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,



length of the 'original' rectangle is  2 inches more than the widthhighlight%28x%29

width x

length (x+2)

If the length and width are each increased by 3 inches

New width: x%2B3

New length: %28x%2B5%29



Question states***

 perimeter of the new rectangle will be 4 inches less than 8 times the width of the original rectangle

P = 2L + 2W = 2%28x%2B5%29+%2B+2%28x%2B3%29+=++8x-4

                    2x+ 10 + 2x + 6 = 8x-4

                            20 = 4x

                         x = 5in, width of the original rectangle. length = 7in.  Good work

Find the dimensions of the New Rectangle:  width = 8in and length 10in.  Good work.

and...

20in+%2B+16in+=+36in+=+8%2A5in+-+4in