SOLUTION: the length of a rectangle is 7 inches less than two times the width. the perimeter of the rectangle is 221 inches. Find the length and the width if the rectangle. (P= 2l+2w) Let x

Algebra ->  Rectangles -> SOLUTION: the length of a rectangle is 7 inches less than two times the width. the perimeter of the rectangle is 221 inches. Find the length and the width if the rectangle. (P= 2l+2w) Let x      Log On


   



Question 663499: the length of a rectangle is 7 inches less than two times the width. the perimeter of the rectangle is 221 inches. Find the length and the width if the rectangle. (P= 2l+2w)
Let x=

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
the length L of a rectangle is 7+in less than two times the width W, we have
L=2W-7in....1
the perimeter of the rectangle is P=221in

P=+2L%2B2W.....plug in L=2W-7in and P=221in

221in=+2%2A%282W-7in%29%2B2w.....solve for W
221in=+4W-14in%2B2W
221in%2B14in=+6W
235in=+6W
235in%2F6=+W
highlight%2839.1666in=+W%29

now find L
L=2W-7in
L=2%2A39.17in-7in
L=78.3333in-7in
L=highlight%2871.3333in%29