SOLUTION: The perimeter of rectangle ABCD is 40 ft. If BC is 3 times as long as CD, what is the length of AD? (BC and CD are suppose to have lines on top of them, and ABCD are points on each

Algebra ->  Rectangles -> SOLUTION: The perimeter of rectangle ABCD is 40 ft. If BC is 3 times as long as CD, what is the length of AD? (BC and CD are suppose to have lines on top of them, and ABCD are points on each      Log On


   

Question 640305: The perimeter of rectangle ABCD is 40 ft. If BC is 3 times as long as CD, what is the length of AD? (BC and CD are suppose to have lines on top of them, and ABCD are points on each corner of a rectangle).
Answer by sachi(548) About Me  (Show Source):
You can put this solution on YOUR website!
let CD =x then BC = 3x
so perimeter= =2(x+3x)=8x=40ft
so x=40/8=5=Ab=CD
& AD=BC=3*5=15 ft ans