SOLUTION: A rectangle has a perimeter of 34in and has an area of 60 in. What is the length of the diagnol of the rectangle? A. 12 in. B. 13 in. C. 15 in. I know the answer is B. 13

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Question 620556: A rectangle has a perimeter of 34in and has an area of 60 in. What is the length of the diagnol of the rectangle?
A. 12 in.
B. 13 in.
C. 15 in.
I know the answer is B. 13 in. however I do not know how to reach that answer

Found 2 solutions by jim_thompson5910, ewatrrr:
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
The perimeter is 34, so 34 = 2L+2W or L+W = 17. Solve for L to get L = 17-W

The area is 60, so 60 = LW. Plug in L = 17-W to get

60 = (17-W)W

Now solve for W. Then use this solution for W to find L.

Once you have L and W. Plug them into the formula

D = sqrt( L^2 + W^2 )

to find the length of the diagonal D

Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!

Hi,
A rectangle has a perimeter of 34in and has an area of 60 in.
P = 2l + 2w = 34in
l + w = 17
l = 17-w
w(17-w) = 60 in^2
w^2 -17w + 60 = 0
factoring
(w - 12)(w - 5) = 0
W = 5 or 12 and L = 5 or 12
D = throwing out the negative solution for unit measure