SOLUTION: Given two rectangles, one with length = l and width = w, and the second rectangle with length = 2l and width = 4w. How much larger will the perimeter of the second rectangle be th

Algebra ->  Rectangles -> SOLUTION: Given two rectangles, one with length = l and width = w, and the second rectangle with length = 2l and width = 4w. How much larger will the perimeter of the second rectangle be th      Log On


   



Question 611157: Given two rectangles, one with length = l and width = w, and the second rectangle with length = 2l and width = 4w. How much larger will the perimeter of the second rectangle be than the perimeter of the first rectangle?
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
perimeter is the sum of the sides.
For the first rectangle, the perimeter is 2l+%2B+2w since the four sides are l , l , w ,w
For the second rectangle, the sides are 2l and 4w. So the sides are 2l, 2l, 4w, 4w. Which sums to 4l+%2B+8w
So how much longer is the second than the first?
%284l%2B8w%29+-+%282l%2B2w%29
%284l-2l%29+%2B+%288w-2w%29
2l+%2B+6w longer