SOLUTION: The perimeter of a rectangle is 48 cm. The length is 6 cm less than twice the width. Which system would model this situation, and what are the length and the width?

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Question 607684: The perimeter of a rectangle is 48 cm. The length is 6 cm less than twice the width. Which system would model this situation, and what are the length and the width?
Answer by sophxmai(62) About Me  (Show Source):
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The perimeter of a rectangle is 48 cm. The length is 6 cm less than twice the width. Which system would model this situation, and what are the length and the width?

Let x=length and y=width
2x%2B2y=48
x%2B6=2y

Solve the 2nd equation for x or y (whichever is more convenient) and then plug into the 1st equation.
x%2B6=2y
x=2y-6

2x%2B2y=48
2%282y-6%29%2B2y=48
4y-12%2B2y=48
6y=60
y=10

Substitute y into a previous equation to solve for x.
x=2y-6
x=2%2810%29-6
x=20-6
x=14

The length is 14cm and the width is 10cm.