SOLUTION: Hi, I am new to geometry. I am a distance education student and cannot fiqure out where to start. The problem is: Find the volume and surface area of a rectangular solid, if it

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Question 60669This question is from textbook Essential Algebra
: Hi, I am new to geometry. I am a distance education student and cannot fiqure out where to start.
The problem is: Find the volume and surface area of a rectangular solid, if its
length is 10 inches, its width is 5 inches, and it is twice as wide as it is deep.
Thanks for your help,
Lee Ann
This question is from textbook Essential Algebra

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Well, a rectangular solid has six faces, opposite pairs of which are identical.
To find the volume of a rectangular solid, use the formula:
V+=+l%2Aw%2Ah Where: l = the length, w = the width, and h = the height.
You are given the length: l = 10" and the width, w = 5"
If it is twice as wide as it is deep (same as height).
So, 2h = w and h = (1/2)w = (1/2)5 = 2.5
The volume is:
V+=+%2810%29%285%29%282.5%29
V+=+125cu. ins.
To find the surface area of the six faces, find the areas of the three pairs of identical faces (2 sides, 2 ends, top & bottom).
One side: A1+=+l%2Ah = %2810%29%2A%282.5%29+=+25 Multiply by 2 for both sides.
2A1+=+2%2825%29 = 50 sq. ins.
For one end: A2+=+w%2Ah = %285%29%2A%282.5%29+=+12.5 Multiply by 2 for both ends.
2A2+=+2%2812.5%29 = 25 sq. ins.
For the top: A3+=+l%2Aw = %2810%29%285%29+=+50 Multiply by 2 for both top & bottom.
2A3+=+2%2850%29 + 100 sq. ins.
Total surface area is: 2A1+%2B+2A2+%2B+2A3+=+50+%2B+25+%2B+100 = 175 sq. ins.