SOLUTION: I have done these problems before but I am stumped..... The area of a rectangular wall is 240 sq. ft. It's length is 6 feet shorter than three times it's width. Find the length

Algebra ->  Rectangles -> SOLUTION: I have done these problems before but I am stumped..... The area of a rectangular wall is 240 sq. ft. It's length is 6 feet shorter than three times it's width. Find the length       Log On


   

Question 606523: I have done these problems before but I am stumped.....
The area of a rectangular wall is 240 sq. ft. It's length is 6 feet shorter than three times it's width. Find the length and width of the wall.
I know A=LW and I set it up as w(3w-6)=240
I got answers that don't work. How do I solve this? Have I set it up correctly??
Thanks,
Tammy
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a rectangular wall is 240 sq. ft. It's length is 6 feet shorter than three times it's width. Find the length and width of the wall.
I know A=LW and I set it up as w(3w-6)=240
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3w^2-6w = 240
w^2-2w-80 = 0
-------
(w-10)(w+8) = 0
width = 10 ft.
length = 3w-6 = 30-6 = 24 ft
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Cheers,
Stan H.
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