SOLUTION: a semicircle of radius r =2x is inscribed in a rectangle so that the diameter of the semicircle is the length of the rectangle. a.) express the area of the rectangle as a fu

Algebra ->  Rectangles -> SOLUTION: a semicircle of radius r =2x is inscribed in a rectangle so that the diameter of the semicircle is the length of the rectangle. a.) express the area of the rectangle as a fu      Log On


   



Question 605054: a semicircle of radius r =2x is inscribed in a rectangle so that the diameter of the semicircle is the length of the rectangle.

a.) express the area of the rectangle as a function of x.
b.) express the perimeter of the rectangle as the function of x.

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
I interpret the problem like this
The length of the rectangle is 4x and the width is 2x .
That makes the area
area=%284x%29%2A%282x%29=8x%5E2 and the perimeter would be
perimeter=2%2A%284x%2B2x%29=2%2A%286x%29=12x