SOLUTION: the area of the table top is 26 square feet, and twice the length is 3 feet shorter than 4 times the width. Find the permeter of the table top

Algebra ->  Rectangles -> SOLUTION: the area of the table top is 26 square feet, and twice the length is 3 feet shorter than 4 times the width. Find the permeter of the table top      Log On


   

Question 591034: the area of the table top is 26 square feet, and twice the length is 3 feet shorter than 4 times the width. Find the permeter of the table top
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
A = L*W
1) L*W = 26 and...
2) 2L = 4W-3 "...twice the length (L) is 3 feet shorter than 4 times the width (W)."
Multiply equation 1) by 2 to get:
2L%2AW+=+52 Substitute for 2L equation 2):
%284W-3%29%2AW+=+52 Simplify.
4W%5E2-3W+=+52 Subtract 52 from both sides.
4W%5E2-3W-52+=+0 Factor this quadratic equation.
%28W-4%29%284W%2B13%29+=+0 Apply the zero product rule.
W-4+=+0 or 4W%2B13+=+0 therefore:
W+=+4 or 4W+=+-13 Discard the negative solution as thw width, W, is a positive quantity.
W+=+4 and
2L+=+4W-3
2L+=+4%284%29-3
2L+=+13 and 2W+=+8
Perimeter, P = 2L+2W
P+=+13%2B8
P+=+21feet.