SOLUTION: Find x then find the perimeter of the rectangle. Base = 3x Height = x-1 Diagonal = 3x+1 What I've already tried: {{{ (x-1)^2 + (3x)^2 = (3x+1)^2 }}} {{{

Algebra ->  Rectangles -> SOLUTION: Find x then find the perimeter of the rectangle. Base = 3x Height = x-1 Diagonal = 3x+1 What I've already tried: {{{ (x-1)^2 + (3x)^2 = (3x+1)^2 }}} {{{      Log On


   

Question 583339: Find x then find the perimeter of the rectangle.
Base = 3x
Height = x-1
Diagonal = 3x+1


What I've already tried:
++%28x-1%29%5E2+%2B+%283x%29%5E2+=+%283x%2B1%29%5E2+

+%28x%5E2-x-x%2B1%29+%2B+3x%5E2+=+%289x%5E2+%2B+3x+%2B+3x+%2B+1%29+
+%284x%5E2+-+2x+%2B1%29+=+%289x%5E2+%2B+6x+%2B+1%29+
+%285x%5E2+%2B+8x+-+0%29+=+0+


Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
(3x)^2 = 3 * x * 3 * x = 9x^2

x^2 - 2x + 1 = 6x + 1

x^2 - 8x = 0 ___ x (x - 8) = 0