SOLUTION: the width of a rectangle is 15m shorter than its length. if its length were increased by 8 m and its width were diminished by 6 m its area will be decreased by 50 sq. m. find its d

Algebra ->  Rectangles -> SOLUTION: the width of a rectangle is 15m shorter than its length. if its length were increased by 8 m and its width were diminished by 6 m its area will be decreased by 50 sq. m. find its d      Log On


   

Question 582312: the width of a rectangle is 15m shorter than its length. if its length were increased by 8 m and its width were diminished by 6 m its area will be decreased by 50 sq. m. find its dimensions.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Width+=x=length-15 --> Length=x%2B15
Area=x%28x%2B15%29=x%5E2%2B15x
New+length=%28x%2B15%29%2B8=x%2B23, New+width=x-6
New+area+=%28x%2B23%29%28x-6%29=x%5E2%2B17x-138=Area-50
x%5E2%2B17x-138=+x%5E2%2B15x-50 --> 17x-138=15x-50 --> 17x-138-15x=15x-50-15x+ --> 2x-138=-50 --> 2x-138%2B138++=-50++%2B138+ --> 2x=88+ --> x=88%2F2 --> x=44 --> length=+44%2B15=59
So highlight%28width=44%29 and highlight%28length=59%29
VERIFICATION
Area+=44%2A59=2596
New length =59%2B8=67 New width =44-6=38 New area=67%2A38=2546=2596-50