SOLUTION: A rectangle has a width of 3X inches and a length that is 8 inches shorter. The area is 825 sq. inches find the dimensions.
X_____, W__________,L___________ , Perimeter________
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X_____, W__________,L___________ , Perimeter________
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Question 568305: A rectangle has a width of 3X inches and a length that is 8 inches shorter. The area is 825 sq. inches find the dimensions.
X_____, W__________,L____________, Perimeter________ Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Width = 3x
Length = 3x-8
Area = L*W
825 = 3x(3x-8)
825=9x^2-24x
9x^2-24x-825=0
Find the roots of the equation by quadratic formula
a= 9 , b= -24 , c= -825
b^2-4ac= 576 + 29700
b^2-4ac= 30276
x1=( 24 + 174 )/ 18
x1= 11.00
x2=( 24 -174 ) / 18
x2= -8.33
Ignore negative value
x = 11
width = 3x = 33 inches
Length = 3x-8 , 33-8=25 inches
Perimeter = 2(L+W)
you can work that out
