Question 558819: What is the area and perimiter of a rectangle with one side of 11 mm and a diagonal of 61 mm?
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! Let x= length
11 = width
61 = diagonal
By Theorem of Pythagoras,
 Reject x=-60!
Perimeter = 2W + 2L
Perimeter = 2*11+ 2*60
Perimeter = 22 + 120 = 132 mm
Area = L*W
Area = 11*60= 660 square mm.
For additional examples and explanation like this, please see my website. To go to my website, use the easy-to-spell and easy-to-remember link www.mathinlivingcolor.com. At the very bottom of this page, there is a link that will take you to my Homepage.
Once you are on my Homepage, for help with the Theorem of Pythagoras, look for the link "Basic, Intermediate, and College Algebra: One Step at a Time," and choose "Basic Algebra", "Chapter 2", "Section 2.10". For topics of Perimeters and Areas, look for the link near the bottom of my Homepage "Topics from Geometry."
Everything on the website is FREE. If you find something you really like, just print your own copy of it!!
If anyone needs to contact me, especially about the website, my Email address is rapaljer@seminolestate.edu. I'll be glad to help you find an explanation on my website to help you with your algebra topic!
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
|
|
|
