SOLUTION: The perimeter of a rectangle is 208 inches. The length exceeds the width by 52 inches. Find the length and the width.
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Question 558711: The perimeter of a rectangle is 208 inches. The length exceeds the width by 52 inches. Find the length and the width. Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! P = 2*(L+W) = 208
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L+W = 208/2 = 104
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L = 104-W
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L = W+52
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L=L, so
104-W = W+52
52 = 2W
W = 26
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L = W+52 = 26+52 = 78
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Check answer with perimeter.
L+W = 26+78 = 104
P = 2*(L+W) = 2*104 = 208
Correct.
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Answer: L=78, W=26
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Done.
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