SOLUTION: The length of a room is 4 less than twice its width. What are the dimensions of the room if the perimeter is 58 feet?

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Question 547289: The length of a room is 4 less than twice its width. What are the dimensions of the room if the perimeter is 58 feet?
Answer by mathie123(224) About Me  (Show Source):
You can put this solution on YOUR website!
Let l be the length of the room and w be the width of the room.
From the question we can get two equations :
2w-4=l (1)
and
2w%2B2l=58+ (2) (this is the formula for perimeter of a rectangle)
Substituing (1) into (2) we get:
2w%2B2%282w-4%29=58
2w%2B4w-8=58
6w-8=58
6w-8%2B8=58%2B8
6w=66
6w%2F6=66%2F6
w=11
Now substituting this value for w into (1) we get:
2%2A11-4=l
22-4=l
l=18

Therefore the room is 18 by 11.

Hopefully this helps, let me know if you still are not sure.