SOLUTION: Two rectangles are similar. One is 5 cm by 12 cm. The longer side of the second rectangle is 8 cm greater than twice it's shorter side. Find it's length and width

Algebra ->  Rectangles -> SOLUTION: Two rectangles are similar. One is 5 cm by 12 cm. The longer side of the second rectangle is 8 cm greater than twice it's shorter side. Find it's length and width      Log On


   

Question 542271: Two rectangles are similar. One is 5 cm by 12 cm. The longer side of the second rectangle is 8 cm greater than twice it's shorter side. Find it's length and width
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Two rectangles are similar. One is 5 cm by 12 cm.
The longer side of the second rectangle is 8 cm greater than twice it's shorter side.
Find it's length and width.
:
Since the rectangles are similar, the relationships between the length and width are the same, so we can write it
:
let x = the shorter side
%28%282x%2B8%29%29%2Fx = 12%2F5
Cross multiply
5(2x+8) = 12x
10x + 40 = 12x
40 = 12x - 10x
40 = 2x
x = 40/2
x = 20 cm is the shorter side
then
2(20)+8 = 48 cm is the length
:
The 2nd rectangle: 48 by 20