SOLUTION: please help me: a square with 4 vertices (0,0), (m,0), (0,m) find the fourth vertex

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Question 529787: please help me: a square with 4 vertices (0,0), (m,0), (0,m) find the fourth vertex

Found 2 solutions by solver91311, swincher4391:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!




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Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
A square, by definition, has equal side length for all 4 sides. So let's use the distance formula between any two adjacent points.
Try, (0,0) (0,m)
sqrt((0-m)^2 + (0,0))
sqrt(m^2)
m
Our side length is m.
Let's assume m is a positive number.
Then (0,0) is our bottom left corner.
(m,0) is our bottom right corner
(0,m) is our top left corner
We need to find the top right corner.
We need to travel m units up from our bottom right corner.
or
We need to travel m units right from our top left corner.
Either way we will end up with the same point (m,m) which is our 4th vertex. So our square is (0,0) (m,0) (0,m) (m,m)