SOLUTION: What is the area of a rectangle that is 5 inches longer than it is wide and if you double the length and subtract 2 inches from the width the area is increased by 52 inches squared
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Question 527516: What is the area of a rectangle that is 5 inches longer than it is wide and if you double the length and subtract 2 inches from the width the area is increased by 52 inches squared?
I tried ...
x(x+5)=x^2+5x
(x-2)(2x+10)=x^2+5x+52
but I dont think Im setting it up right...
Can you help me set it up? And/or possibly give me the solution so I can figure out how to get to it for future problems? Answer by scott8148(6628) (Show Source):
