SOLUTION: A rectangular garden is twice as long as it is wide and is surrounded by a sidewalk that is 4 ft wide. The area of the sidewalk is 1024 ft sq. Find the
dimensions of the garden.
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-> SOLUTION: A rectangular garden is twice as long as it is wide and is surrounded by a sidewalk that is 4 ft wide. The area of the sidewalk is 1024 ft sq. Find the
dimensions of the garden.
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Question 523229: A rectangular garden is twice as long as it is wide and is surrounded by a sidewalk that is 4 ft wide. The area of the sidewalk is 1024 ft sq. Find the
dimensions of the garden. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! width of garden x
length of garden= 2 x
sidewalk width= 4
Area of garden + walkaway= x*( 2 x)
Area of sidewalk 1024 M^2
with including walkway x + 8
length including walkway(2x +8 )
Total area – Area ofgarden = Area of sidewalk
Total area = (x+8)*( 2x+8)
(x+8)*( 2x+8)- x*(2x)=1024
2x^2+8x+16x+64-2x^2=1024
x^2 + 24 x + 64 = 1024
24 x = 960
/ 24
x= 40 Meters width of garden
80 Meters length of garden
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