SOLUTION: Determine the perimeter and the area of a rectangle with a length of 12.1 m and a width of 7.3m. isbn: 0618372628

Algebra ->  Rectangles -> SOLUTION: Determine the perimeter and the area of a rectangle with a length of 12.1 m and a width of 7.3m. isbn: 0618372628      Log On


   

Question 51428: Determine the perimeter and the area of a rectangle with a length of 12.1 m and a width of 7.3m.
isbn: 0618372628
Answer by rchill(405) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a rectangle is given as length multiplied by width. In this case, that means 12.1*7.3, which is 88.33 square meters. The perimeter of a rectangle is found by adding all the sides together. Because a rectangle has 4 sides (2 lengths and 2 widths), the equation to find the perimeter is defined as 2l%2B2w where l is the length and w is the width. Substituting in your values of 12.1 and 7.3 produces the equation 2%2A12.1%2B2%2A7.3, which simplifies to 24.2%2B14.6, and that equates to 38.8 m.