You can put this solution on YOUR website! What is the dimensions of a rectangle
whose perimeter is 112 and the width is 3/4 the length?
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Let length be L
The width = (3/4)L
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Equation:
Perimeter = 2(L + (3/4)L)
112 = 2(7/4)L
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56 = (7/4)L
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L = (4/7)56
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Length = 32
Width = (3/4)32 = 24
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Cheers,
Stan H.
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