SOLUTION: the length of a rectangle is 10 units longer than its width. if the total perimeter of the rectangle is 44 units, what is the width?
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-> SOLUTION: the length of a rectangle is 10 units longer than its width. if the total perimeter of the rectangle is 44 units, what is the width?
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Question 499272: the length of a rectangle is 10 units longer than its width. if the total perimeter of the rectangle is 44 units, what is the width? Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! P = perimeter
L = length
W = width
P = 2L + 2W = 2(L+W)
P = 44
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L = W+10
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Substitute
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2(W+10) + 2W = 44
2W + 20 + 2W = 44
4W = 24
W = 6
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L = W+10
L = 6+10
L = 16
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Check your work!
2L = 32
2W = 12
32+12 = P = 44
Correct.
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Re-read the question to make sure you answer it.
The width is 6.
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Done.
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