SOLUTION: The length of a rectangle is increased by 60% By what percent would the width have to be decreased to maintain the same area?

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Question 487624: The length of a rectangle is increased by 60% By what percent would the width have to be decreased to maintain the same area?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is increased by 60% By what percent would the width have to be decreased to maintain the same area?
:
let x = the decimal equiv decrease of the width
:
Write an area equation
Original area = new area
L * W = 1.6L * xW
Divide both sides by LW
1 = 1.6 * x
divide both sides by 1.6
1%2F1.6 = x
x = .625,
new width = .625*old width, therefore
1 - .625 = .375 * 100 = 37.5 decrease in the width to have the same area