SOLUTION: The side of one square is 3 cm longer than the side of a second square. If the combined area is 65 cm^2, find the lengths of the sides of both squares.

Algebra ->  Rectangles -> SOLUTION: The side of one square is 3 cm longer than the side of a second square. If the combined area is 65 cm^2, find the lengths of the sides of both squares.      Log On


   

Question 485464: The side of one square is 3 cm longer than the side of a second square. If the combined area is 65 cm^2, find the lengths of the sides of both squares.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Of the final grades received by the students in a certain math course,
1/5 are A ’s, 1/4 are B ’s, 1/2 are C ’s and the remaining 10 grades are D ’s.
What is the number of students in the course?
:
Let x = total number of students
:
x = 1%2F5x + 1%2F4a + 1%2F2x + 10
Multiply by 20 to clear the denominator
20x = 20*1%2F5x + 20*1%2F4a + 20*1%2F2x + 20(10)
Cancel the denominators and we have
20x = 4x + 5x + 10x + 200
20x = 19x + 200
20x - 19x = 200
x = 200 students
;
You can check the solution, replace x with 200 in the original equation