SOLUTION: Suppose a square garden has an area of 16 x2 square feet. If one side is made 4 inches longer and the other side 2 inches shorter, what is the area of the resulting garden?

Algebra ->  Rectangles -> SOLUTION: Suppose a square garden has an area of 16 x2 square feet. If one side is made 4 inches longer and the other side 2 inches shorter, what is the area of the resulting garden?       Log On


   

Question 485339: Suppose a square garden has an area of 16 x2 square feet. If one side is made 4 inches longer and the other side 2 inches shorter, what is the area of the resulting garden?
Found 2 solutions by mananth, MathLover1:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Area = 16x^2
side = 4x
4x +4 one side
4x-2 other side
(4x+4)(4x-2)
16x^2-8x+16x-8
16x^2+8x-8 is the area of the second square

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

given:
A=16+%2A2ft%5E2=32ft%5E2......so, one side is a=16 and other side is b=2

If one side a=16ftis made 4in=0.3ft longer we will have a=16ft-0.3ft=15.7ft

and if the other side b=2 is made 2in=+0.17ft+ shorter we will have
b=2ft-0.17ft=1.83ft
than area will be
A=15.7+%2A1.83ft%5E2=28.73ft%5E2