SOLUTION: Find the sum of the areas of the two rectangles. Write your answer in factored form. Rectangle 1 has a length of 1 divide by x-1 and a width of x-2 Rectangle 2 has a length of 2

Algebra ->  Rectangles -> SOLUTION: Find the sum of the areas of the two rectangles. Write your answer in factored form. Rectangle 1 has a length of 1 divide by x-1 and a width of x-2 Rectangle 2 has a length of 2       Log On


   

Question 484195: Find the sum of the areas of the two rectangles. Write your answer in factored form.
Rectangle 1 has a length of 1 divide by x-1 and a width of x-2
Rectangle 2 has a length of 2 divided by x+1 and a width of x
Found 2 solutions by jorel1380, mananth:
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
(x-2)/(x-1)+2(x+1)/x=
x(x-2)/x(x-1)+2(x-1)/x(x-1)=
x2-2x+2x-2/x2-x=x2-2/x2-x..

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Rectangle 1 has a length of 1 divide by x-1 and a width of x-2
Rectangle 2 has a length of 2 divided by x+1 and a width of x
Rectangle 1 Area =%281%2F%28x-1%29%29%2A%28x-2%29
Rectangle II Area =%282%2F%28x%2B1%29%29%2Ax
Add Them
%281%2F%28x-1%29%29%2A%28x-2%29+%282%2F%28x%2B1%29%29%2Ax

%28%28x-2%29%2F%28x-1%29%29%2B%282x%2F%28x%2B1%29%29
LCD = (x+1)(x-1)
%28%28%28x%2B1%29%28x-2%29%29%2B%282x%28x-1%29%29%29%2F%28%28x%2B1%29%28x-1%29%29
%28x%5E2-x-2%2B2x%5E2-2x%29%2F%28%28x%2B1%29%28x-1%29%29
%283x%5E2-3x-2%29%2F%28%28x%5E2-1%29%29