SOLUTION: THE PERIMETER OF A RECTANGLE IS 102 INCHES. THE LENGTH EXCEEDS THE WIDTH BY 9 INCHES. FIND THE LENGTH AND THE WIDTH

Algebra ->  Rectangles -> SOLUTION: THE PERIMETER OF A RECTANGLE IS 102 INCHES. THE LENGTH EXCEEDS THE WIDTH BY 9 INCHES. FIND THE LENGTH AND THE WIDTH      Log On


   

Question 466352: THE PERIMETER OF A RECTANGLE IS 102 INCHES. THE LENGTH EXCEEDS THE WIDTH BY 9 INCHES. FIND THE LENGTH AND THE WIDTH
Found 2 solutions by rfer, MathLover1:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
2x+2(2x+9)=102
You do the calculation.
x=width

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
the perimeter of rectangle is P=2%28L%2BW%29
given:
P=102in
L=W%2B9in
2%28L%2BW%29=102in
2%28L%2BW%29%2F2=102in%2F2
L%2BW=51in..replace L with W%2B9in
W%2B9in%2BW=51in
2W=51in-9in
2W=42in
2W%2F2=42in%2F2
W=21in
L=W%2B9in
L=21in%2B9in
L=30in