SOLUTION: the preimeter of a rectangle is 43in. more than the length. the width is 10in. find the length of the rectangle
Algebra ->
Rectangles
-> SOLUTION: the preimeter of a rectangle is 43in. more than the length. the width is 10in. find the length of the rectangle
Log On
You can put this solution on YOUR website! "the preimeter of a rectangle is 43in. more than the length. the width is 10in. find the length of the rectangle"
x = length
10 = width
x + 43 = perimeter {perimeter is 43 more than the length}
Perimeter of a rectangle = 2(length) + 2(width)
x + 43 = 2x + 2(10) {substituted into formula for perimeter}
x + 43 = 2x + 20 {multiplied 2 by 10}
43 = x + 20 {subtracted x from both sides}
x = 23 {subtracted 20 from both sides}
