SOLUTION: Find the dimensions of the rectangle or triangle that has the given area: Area: 34 square meters length is (x-4)m Width is (x+11)m

Algebra ->  Rectangles -> SOLUTION: Find the dimensions of the rectangle or triangle that has the given area: Area: 34 square meters length is (x-4)m Width is (x+11)m      Log On


   

Question 461273: Find the dimensions of the rectangle or triangle that has the given area:
Area: 34 square meters
length is (x-4)m
Width is (x+11)m
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
Area: A=34m%5E2
length is L=%28x-4%29m
Width is W=%28x%2B11%29m
A=LW
34m%5E2=%28x-4%29m%2A%28x%2B11%29m
34m%5E2=%28xm-4m%29%2A%28xm%2B11m%29
34m%5E2=%28xm%29%5E2%2B11xm%2Am-4xm%2Am-44m%5E2

34m%5E2=%28xm%29%5E2%2B7xm%5E2-44m%5E2
0=%28xm%29%5E2%2B7xm%5E2-44m%5E2-34m%5E2
{{(x^2m^2+7xm^2-78m^2=0}}}
%28%28x%29%5E2%2B7x-78%29m%5E2=0

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-7+%2B-+sqrt%28+7%5E2-4%2A1%2A%28-78%29+%29%29%2F%282%2A1%29+

x+=+%28-7+%2B-+sqrt%28+49%2B312+%29%29%2F2+


x+=+%28-7+%2B-+sqrt%28361+%29%29%2F2+

x+=+%28-7+%2B-+19%29%2F2+.we will take only positive root; length and width cannot be negative
x+=+%28-7+%2B+19%29%2F2+

x+=+12%2F2+
x+=+6....now find L=%28x-4%29m and W=%28x%2B11%29m
L=%286-4%29%2Am=2m
W=%286%2B11%29%2Am=17m