SOLUTION: I have a room that is 12 ft x 20 ft x 8 ft high.
The lenght of the diagonal is 23.3 feet:
d^2 = a^2 + b2
d^2= 12^2 + 20^2
dsq = 144 + 400
d^2 (sqrt) = 544 (sq rt)
d= 23.32
Algebra ->
Rectangles
-> SOLUTION: I have a room that is 12 ft x 20 ft x 8 ft high.
The lenght of the diagonal is 23.3 feet:
d^2 = a^2 + b2
d^2= 12^2 + 20^2
dsq = 144 + 400
d^2 (sqrt) = 544 (sq rt)
d= 23.32
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Question 449039: I have a room that is 12 ft x 20 ft x 8 ft high.
The lenght of the diagonal is 23.3 feet:
d^2 = a^2 + b2
d^2= 12^2 + 20^2
dsq = 144 + 400
d^2 (sqrt) = 544 (sq rt)
d= 23.32 ft
How do I now figure out the angle of that diagonal?
I want to do the work, but I don't know what equation to use to find the answer? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! There are 3 angles. One of them is 90º, between the walls.
The smaller angle is the arctan(12/20) =~ 31º
The larger is 90 - the smaller = 59º
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The height is not a factor.
