SOLUTION: The area of a rectangle is 52.7 square meters. Its length is 2 meters more than its width. Find its dimensions. I know it's more than 6 x 8 - and it's less than 7 x 9 - but ho

Algebra ->  Rectangles -> SOLUTION: The area of a rectangle is 52.7 square meters. Its length is 2 meters more than its width. Find its dimensions. I know it's more than 6 x 8 - and it's less than 7 x 9 - but ho      Log On


   

Question 447871: The area of a rectangle is 52.7 square meters. Its length is 2 meters more than its width. Find its dimensions.
I know it's more than 6 x 8 - and it's less than 7 x 9 - but how do you figure the fractions?
Thanks!
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a rectangle is 52.7 square meters. Its length is 2 meters more than its width. Find its dimensions.
---------------------------------
Let the width be "w".
Then length is "w+2".
----
Area = (length)(width)
52.7 = (w+2)w
-----
w^2 + 2w - 52.7 = 0
-----
Quadratic Equation:
w = [-2 +- sqrt(4-4*1*-52.7)]/2
----
w = [-2 +- sqrt(214)]/2
---
w = [-2 +- 14.66]/2
---
Positive solution:
w = [-2 + 14.66]/2 = 12.66/2 = 6.33 (width)
w+2 = 8.33 (length)
=============================
Cheers,
Stan H.
==============