SOLUTION: The length is 5 units more than the width. The perimeter is 9 times times the width. How do you find the length and the width of the rectangle described
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Question 447323: The length is 5 units more than the width. The perimeter is 9 times times the width. How do you find the length and the width of the rectangle described Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! P=2L+2W
9W=2L+2W
2L=7W
L=W+5
9W=2(W+5)+2W
7W=2W+10
5W=10
W=2
L=7
The length is 7 units, the width is 2 units..
